if the equation mx^2+2x+m=0 has two unequal roots,then find the value of m
Answers
Answered by
50
given
mx square + 2x +m=0
b square- 4ac=0
2 square -4m square
>4-4m square =0
>-4m square =-4
>m square =1
m =+1 or -1
mx square + 2x +m=0
b square- 4ac=0
2 square -4m square
>4-4m square =0
>-4m square =-4
>m square =1
m =+1 or -1
Answered by
22
Given,
a = m, b = 2, and c = m
This equation has unequal roots, its discriminant is greater than 0.
∴ b² - 4ac 0
⇒2² - 4 * m*m 0
⇒4-4m²0
⇒m²-(4/4) = -1
⇒ ∴ m = -1
a = m, b = 2, and c = m
This equation has unequal roots, its discriminant is greater than 0.
∴ b² - 4ac 0
⇒2² - 4 * m*m 0
⇒4-4m²0
⇒m²-(4/4) = -1
⇒ ∴ m = -1
duragpalsingh:
Please mark it as brainliest!
Similar questions