Question

if the equation
$x { }^{2} + kx + k = 0$
has only one solution , find the possible values of k.

Answer 1

Heyy mate ❤✌✌❤

Here's your Answer...

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X^2+kx+k=0

this equation has two distinct real solution.
now,

= b^2 -4ac = 0


if b = 1 , a = 1.

= k^2 - 4*(1)*k > 0

= k^2 -4k. > 0

= k (k-4) > 0

then ,

k >0 and k> 4.
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