Question

If the equation x^2 – 4x + a = 0 has no real roots, then ​

Answer 1

Answer:

Any no. greater than 4

Step-by-step explanation:

Let the quadratic equation be a^2x+bx+c=0

For no real roots,

Discriminant<0

b^2 - 4ac<0

Now on comparing,

a=1, b=-4, c=a

(-4)^2 - 4(1)(a)<0

16-4a<0 ( I have taken minus sign common so the inequality changes)

4a-16>0

4a>16

so, a>4

Answer 2

Answer:

i hope you had satisfied