Question

If the equation x (square) + 4x+k=0 has real and distinct roots, then value of k is K

Answer 1

Heya Friend !!!

Here's ur ans with solution :)

▶ x² + 4x + k = 0


➡ As we know that the quadratic equation has real and distinct roots if when discriminant is greater than zero.

that is, D > 0 ..... ( i )

And also,

D = b² - 4ac ..... ( ii )

Here,

⭐ a = 1

⭐ b = 4

⭐ c = k

So, putting these value in equation ( ii )

D = b² - 4ac

= ( 4 )² - 4 × 1 × k

= 16 - 4k


And from ( i )

D > 0

16 - 4k > 0

16 > 4k

16/4 > k

4 > k

So,

The value of k can be any positive integer except 4 and the numbers less than 4.


@Altaf

Answer 2

The correct answer is

$k < 4$

Hope it will be helpful for you.

So, please mark it as the brainliest answer.