if the equation x square -ax+1=0 has two distinct roots, than
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hey mate your answer
x+1)(x−2)+x=0⇒x
2
−x+x=0⇒x
2
−2=0
D=b
2
−4ac=0−4(1)(−2)=8>0
∴ Given equation has two distinct real roots
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https://www.shaalaa.com/question-bank-solutions/if-equation-x2-ax-1-0-has-two-distinct-roots-then-solutions-quadratic-equations-factorization_63517
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