Question

if the equation x square - bx + 1 = 0 has two distinct real roots then which of the following is correct? (a)b square - 4a >0 (b) b square - 4 >0 (c) b square - 4=0 (d) b square - 4c>0
​

Answer 1

Answer :

If the equation is x² - bx + 1 = 0

it is given that the equation has two distinct real roots then,

• b² - 4ac > 0 is correct ✓

━━━━━━━━━━━━━━━━━━━━━━━━━

More About Discriminant :

b² - 4ac > 0 - two real distinct roots

b² - 4ac < 0 - imaginary roots

b² - 4ac = 0 - two real roots