Question

if the equation x square - bx + 1 = 0 has two distinct roots then ​

Answer 1

Answer:

i have written a instead of b sorry!!

The discriminant of x^2 - ax + 1 is d = a^2 - 4. 

(1) If the equation has exactly one real root, then d = 0 

a^2 - 4 = 0 

a^2 = 4 

|a| = 2 

(2) If the equation has two real roots, then d > 0 

a^2 - 4 > 0 

a^2 > 4 

|a| > 2 

(3) If the equation has two complex-valued roots, then d < 0 

a^2 - 4 < 0 

a^2 < 4 

|a| < 2

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