Question

If the equation x² – (2 + m)x + (-m² – 4m – 4) = 0 has coincident roots, then find value of m ?​

Answer 1

b^-4ac

=>-(2+m)^2 - 4(1)(-m^2 - 4m-4)>or=to zero

=>(-2)^2 +m^2 - 2(-2)(m)+4m^2 +16m-16

=>4+m^2 +4m+4m^2 +16m-16

=>5m^2 +20m-12