if the equation x2+ 4x+ k=0 has real and distinct roots, then find the values of k.
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Answered by
5
b^2-4ac =0
a=1. b =4. c=k
(4)^2-4×1×k >0
16–4k >0
–4k +16>0
k=4, –4
a=1. b =4. c=k
(4)^2-4×1×k >0
16–4k >0
–4k +16>0
k=4, –4
Amankhan993653:
it's wrong
method is wrong
in question it's saying that Real And Distinct Roots not Real And Equal Roots
D>0
thanks for telling me
it's OK bro
no worry Mera bhot mistake huwa tha
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7
Hiiii
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Below in the Attachment You can Find the Solution
Please If You Like it
Mark As BrainList
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