If the equation x² + 4x + k = 0 has real and distinct roots, then
A. k < 4
B. k > 4
C. k ≥ 4
D. k ≤ 4
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The value of k in the equation x² + 4x + k = 0 is given as k < 4. Hence, option (A) is the correct answer.
• It is given that the equation has real and distinct roots.
A quadratic equation can have real and distinct roots if the following condition is satisfied :
Discriminant > 0
• Now, discriminant of an equation is given as :
D = b² - 4ac,
where a is the coefficient of x²,
b is the coefficient of x,
and c is the constant in the equation.
• Therefore, for the given equation, a = 1, b = 4, c = k
∴ b² - 4ac > 0
=> 4² - 4.1.k > 0
=> 16 - 4k > 0
=> 16 > 4k
=> 4k < 16
=> k < 16 / 4
=> k < 4
∴ The value of k is less than 4 (option A).
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