Question

If the equation x² – bx + 1 = 0 does not possess real roots, then
A. – 3 < b < 3
B. – 2 < b < 2
C. b > 2
D. b < – 2

Answer 1

Given:

The equation x² – bx + 1 = 0 does not possess real roots

To find:

Range of b

Answer:

• x² – bx + 1 = 0
• For equations that do not possess any real roots condition is b² -4ac < 0.
• Here a=1 , b= - b and c=1
• We get, D= b² -4 < 0

-2<b<2

Hence, option B is the right answer.

Answer 2

Step-by-step explanation:

a -3

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