Question

If the equation x²+4x+k=0 has real and district roots, then find the value of k.​

Answer 1

Let's solve for k.

x2+4x+k=0

Step 1: Add -x^2 to both sides.

x2+k+4x+−x2=0+−x2

k+4x=−x2

Step 2: Add -4x to both sides.

k+4x+−4x=−x2+−4x

k=−x2−4x

Answer:

k=−x2−4x

$\sf{\blue{\underbrace{\underline{\orange{HENCE\; VERIFIED✓}}}}}$