if the equation X2 -bx+1=0 has two distinct real roots then which of the following is correct
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Answered by
71
Answer:
b-4a}
b- 4<0
b-4=0
b-4c<o
Answered by
6
Given : x² - bx + 1 = 0 has two distinct real roots .
To find : value of b
Solution :
x² - bx + 1 = 0 has two distinct real roots
D = b² - 4ac in ax² + bx + c = 0
D < 0 imaginary roots
D ≥ 0 , real roots
D = 0 equal roots
two distinct real roots
=> D > 0
(-b)² - 4(1)(1) > 0
=> b² - 4 > 0
=> (b + 2)(b - 2 ) > 0
=> b > 2 or b < -2
b ∈ ( -∞ , - 2) U ( 2 , ∞ )
b ∈ ( -∞ , - 2) U ( 2 , ∞ )
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