If the equation x4 - 4x3 + ax2 + bx + 1 = 0 has four
positive roots, find a and b.
Answers
Answered by
1
ANSWER:
a=16,b=4
STEP BY STEP EXPLANATION;
X^2 -4X^3 +AX^2+BX+1=0
(4)^4-4(4)^3+a(4)^2+b(4)+1=0
256-256+16a+4b+1=0
16a+4b+1=0
16a+1=0
a=16
4b+1=0
b=4
✌️HOPE THIS WILL HELP YOU ✌️
Answered by
1
Answer:
Tujhse Mera positive roots is equal to find a and b if the equation is x square - 4 x 3 + A X 2 + bx + 1 is equal to zero has 4 then the answer is equal to 1 by 4 into 4 by 1 into 1 by 4 into 4 by 1 is equal to X + 2 + bx + 1 + 21 + 12 + 14 + 1 floor on floor
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