If the error in measurement of momentum of a particle is 10% and mass is known exactly, the permissible error in determination of kinetic energy is ?
A. 20%
B. 21%
C. 5%
D. 10%
Answers
Answered by
122
We know,
K= 1/2 × MV²
We know that 1/2 & M are constants and the only variable thing here is its velocity
So the error only depends on velocity
Using the equation
ΔK / K =ΔV / V + 1
so that,
∴ ( 2 × 10 ) + 1
= 21 %
K= 1/2 × MV²
We know that 1/2 & M are constants and the only variable thing here is its velocity
So the error only depends on velocity
Using the equation
ΔK / K =ΔV / V + 1
so that,
∴ ( 2 × 10 ) + 1
= 21 %
sahbahasan:
I am talking about this equation - ΔK / K =ΔV / V + 1
Answered by
56
If the error in measurement of momentum of a particle is 10% and mass is known exactly, the permissible error in determination of kinetic energy is 21%
Using the equation
ΔK / K =ΔV / V + 1
so that,
∴ ( 2 × 10 ) + 1
= 21 %
Using the equation
ΔK / K =ΔV / V + 1
so that,
∴ ( 2 × 10 ) + 1
= 21 %
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