Question

If the error in the measurement of radius is 2 % then the error in the determination of volume of the sphere will be ?
a)8℅
b)2℅
C)4℅
D)6℅
This is one of my school questions can you please tell me the procedure to solve.. don't spam please​

Answer 1

Given :

Percentage error in measurement of radius of sphere = 2%$\%$

To Find :

We have to find percentage error in determination of volume of the sphere$.$

Solution :

Volume of sphere is given by

⇒ V = 4/3πR³

Percentage error in volume is

⇒ ΔV/V × 100% = 3(ΔR/R × 100%)

⇒ ΔV/V × 100% = 3(2%)

⇒ ΔV/V × 100% = 6%