Question

If the error in the measurement of radius of a sphere is 2%, then the error in the determination of the

volume of the sphere will be– (a) 4%, (b) 6%, (c) 8%, (d) 2% .​

Answer 1

Answer:

Percentage error in volume VΔV×100=3×rΔr×100=3×2=6 %

Answer 2

Answer:

Reffered to the attachment

Explanation:

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Warm regards:Miss Chikchiki