If the error in the measurement of radius of a sphere is2%.what will be the error in determination of volume of the sphere?
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6%
vol=4/3r^3
deltaV/V = 3×delta r/r
Delta r =2%
4/3=constant
deltaV/V=3×2%
=6%
vol=4/3r^3
deltaV/V = 3×delta r/r
Delta r =2%
4/3=constant
deltaV/V=3×2%
=6%
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