If the error in the measurement of sphere is 2%,then the error in the determination of the vol of the sphere will be ?
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Answer:
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Explanation:
Percentage error in radius is given as 2% i.e.
r
Δr
×100=2 %
Volume of sphere V=
3
4π
r
3
Percentage error in volume
V
ΔV
×100=3×
r
Δr
×100=3×2=6 %.
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