Physics, asked by gsreenivasulu8795, 6 months ago

If the error in the measurement of sphere is 2%,then the error in the determination of the vol of the sphere will be ?

Answers

Answered by manjitkaur1621

1

Answer:

plz mark brainliest

Explanation:

Percentage error in radius is given as 2% i.e.

r

Δr

×100=2 %

Volume of sphere V=

3

4π

r

3

Percentage error in volume

V

ΔV

×100=3×

r

Δr

×100=3×2=6 %.

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