Question

If the far point of a myopic person is 75 cm, what should be the focal length of thelens used to rectify this defect?

Answer 1

Answer:

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Answer 2

Answer:

-1.33

Explanation:

Far point of the defective eye (v) = -75cm  (Given)

Object length (u) = infinity  ∞ (Given)

According to the formula of lens -

1/f = 1/v-1/u

1/f = 1/-75 - 1/∞

1/f = 1/-75

f = -75

Power of corrective lens = 1/ focal length of the lens

p = 1/-0.75

p = -1.33

Therefore, the focal length of thel ens used to rectify the defect should be -1.33.