Ranjini makes arrangements for a candle-light dinner and tops it with a dessertof gelatin filled blue berries. If a blueberry that appears at an angle of 45° to thenormal in air is really located at 300 to the normal in gelatin, what is the index ofrefraction of the gelatin?
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Answer:
1.41
Explanation:
According to the Snell's Law any angles with respect to a normal and the indices of refraction in any two media are represented by the following equation:
n1sinθ1 = n2sinθ2
Since the index index of refraction of air is 1.00
Therefore,
n(sin30) = 1.00(sin45),
n = sin(45) / sin(30)
n = ( 1/√2)/(1/2)
n = ( 0.707)/(0.50)
n = 1.41
Therefore, the index ofrefraction of the gelatin is 1.41
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