if the fifth term of a an ap is 1/8 and eighth term is 1/5 find the sum of 80 terms
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Answer:
⇒4th term=11
∴ a+3d=11
⇒8th term=2(4th term)+5
⇒a+7d=27
⇒(a+7d)−(a−3d)=27−11
⇒4d=16
⇒d=4
⇒a=−1
Formula: Sn = 2n
[2a+(n−1)d]
Sum of first 50 terms =
50/2 (2(−1)+49(4))
=25(194)=4850
4850
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