Question

If the figure, line AC & timeline BD interesed at point P. answer me fast please​

Answer 1

Answer:

Let AB be the chord and O be the centre of the circle.

Let AB be the chord and O be the centre of the circle.Let OC be the perpendicular drawn from O to AB.

Let AB be the chord and O be the centre of the circle.Let OC be the perpendicular drawn from O to AB.We know, that the perpendicular to a chord, from the centre of a circle, bisects the chord.

Let AB be the chord and O be the centre of the circle.Let OC be the perpendicular drawn from O to AB.We know, that the perpendicular to a chord, from the centre of a circle, bisects the chord.AC = CB = 3 cm

Answer 2

Answer:

Given:  PA=6 cm, PB=3 cm, PC=2.5 cm, PD=5 cm 

PDPA=56

PCPB = 2.53 = 56

Thus, PDPA=PCPB

In △APB and △DPC,

PDPA=PCPB      ...Given

∠APB=∠DPC        ...Vertically opposite angles

Hence, △APB∼△DPC           ....S.A.S test of similarity

Hence, ∠A=∠D=30o

Now, In △APB,

Sum of angles =180o

∠A+∠B+∠APB=180

30+50+∠B=180o

∠B=100∘

Step-by-step explanation:

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