Question

If x³-ax²+6x-a is divided by (x-a), then the remainder is

Answer 1

Answer:

Step-by-step explanation ;

Let f(x) = x³ - ax² + 6x - a

So,

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When,

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f(a) = x³ - ax² + 6x - a

=> (a)³ - a×(a)² + 6×a - a

=> a³ - a³ + 6a - a

=> 5a

Therefore,

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Remainder = 5a

Answer 2

EXPLANATION:-

let p(x)=x³-ax²+6x-a

and f(x)=x-a

Let's use remainder theorem over here :-

x-a=0

x=a

Put x=a in p(x)\,we get:-

p(a)=a³-aa²+6a-a

p(a)=a³-a³+6a-a

p(a)=5a

So the remainder will 5a