If the first, second, and last term of an AP are a, b, 2a respectively, what is its sum?
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Answered by
1
a+b+2a=3a+b
I guess this will be the answer
I guess this will be the answer
Answered by
4
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.P : a , b , . . . . . . . . . . . . . .2a
1st term= a1 = a
2nd term = a2= b
nth term = an = 2a
d = a2 - a1 = b-a
an = a1 + (n-1)d = a + (n-1)(b-a) = 2a
(n-1)(b-a) = a
(n-1) = a / (b-a)
n = a / (b-a) + 1 = b / ( b -a )
Sn = n / 2 * ( a1 + an) = b / 2(b-a) * ( a + 2a) = 3ab / 2(b-a)
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➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬
.P : a , b , . . . . . . . . . . . . . .2a
1st term= a1 = a
2nd term = a2= b
nth term = an = 2a
d = a2 - a1 = b-a
an = a1 + (n-1)d = a + (n-1)(b-a) = 2a
(n-1)(b-a) = a
(n-1) = a / (b-a)
n = a / (b-a) + 1 = b / ( b -a )
Sn = n / 2 * ( a1 + an) = b / 2(b-a) * ( a + 2a) = 3ab / 2(b-a)
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