If the first term of a G.P. is 2 and sum to infinity is 6. Find the common ratio.
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➡️ Solution:
As we know that sum of infinite terms of a GP is given by

here a is the first term and r is common ratio
Given that
a = 2
S∞= 6

Hope it helps you.
As we know that sum of infinite terms of a GP is given by
here a is the first term and r is common ratio
Given that
a = 2
S∞= 6
Hope it helps you.
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