Question

if the first term of an A.p is 2 and common difference is 4 then the sum of ots 40th term is​

Answer 1

a=2

d=4

t40=a+39d

=2+39×4

=158

sum of 40 terms=40/2(2+158)

=20×160

=3200

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Answer 2

275

Step-by-step explanation:

sum of n terms = n/2 (2a+(n-1)d)

here a = 2, d = 4 n = 40

= 40/2 (2×2+ (40-1)4)

= 20 ( 4 + 39/4)

= 20 (16 + 39)/4

= 5 × 55

= 275