Question

if the first term of an ap is -5 and the common difference is 2 then the sum of the first 6 term is​

Answer 1

Answer:

a=-5,d=2

Sn=n/2[2a+(n-1)*d]

S6=6/2[2*(-5)+(6-1)*2]

=3[-10+10]

=3

S6=3

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Hi DEAR,

a = -5

c.d.= 2

sum of AP = n/2[2a+(n-1)d]

where, n = no of terms

ACCORDINGLY,

6/2[-10+(5)2]

3[0]

0

HOPE IT HELPS...