if the first term of an AP is -5 and the common difference is 2 then the sum of 6 term is
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Answered by
1
Answer:
0
Step-by-step explanation:
Here
a=-5
d=2
n=6
Sñ=n/2(2a+(n-1)d)
=6/2(2×-5+(6-1)2)
=3(-10+10)
=3×0
=0
Answered by
0
Answer:
a= -5
d=2
n= 6
an=a(n-1)×d
an=-5 +( 6 -1 ) ×2
an= -5 +( 5 ) ×2
an = -5 + 10
an = +5
hence an is 5
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