if the first term of an Arithmetic sequence is (n) and common difference is 2n . then prove that the sum of first n terms is
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Step-by-step explanation:
a=n , c.d = 2n , term = n
sn = n/2{2n+(n-1)2n}
=n/2(2n+2nsquare- 2n)
=n/2•2nsquare
answer is n cube
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