if the first term of AP is-5 and the common difference of in 2, then the sum of the first 6 time is
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Step-by-step explanation:
Given that,
1st term of an A. P. = a = - 5 and
Common difference = d = 2
∴Sum of the first n terms = Sn = n /2 [ 2a + ( n - 1 ) d ]
Sum of the first 6 terms
=S6 = 6/ 2 [ 2× ( - 5 ) + ( 6 - 1 ) × 2 ]
= 3 [ - 10 + ( 5 ) × 2 ]
= 3 [ - 10 + 10 ]
= 3 [ 0 ]
= 0 is the answer.
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