Question

If the first three terms of an AP are 9p, 4q
and 7p, then find the ratio of p and q.​

Answer 1

Answer:

$\frac{1}{2}$

Step-by-step explanation:

$9p - 4q = 4q - 7p$

therefore

$16p = 8q$

hence,

$\frac{p}{q} = \frac{8}{16} = \frac{1}{2}$

Answer 2

Answer:

$\frac{p}{q} = \frac{1}{2}$

Step-by-step explanation:

$let \: a \: \: b \: \: c \: \: is \: the \: first \: term \: second \: term \: \\ third \: term \: respectvely \\ a = 9p \: \: b = 4q \: \: c = 7p \\ \\as \: we \: know \: in \: ap \: \\ nth \: term \: = a + (n - 1) \times d \\ so \: let \: the \: common \: difference \: is \: d \\ b = 9p + d \\ 4q = 9p + d.........(1) \\ \\ c = 9p + 2d \\ 7p = 9p + 2d \\ d = - p \\ from \: (1) \\ 4q = 8p \\ \frac{p}{q} = \frac{1}{2} \\ \\ hope \: it \: will \: help \: you$