if the first three terms of an ap are x,y and 2x,then find ratio of x and y.
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Step-by-step explanation:
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Answered by
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Answer:
Step-by-step explanation:
Let the AP series be x, x + d, x + 2d ..
x + ( n - 1 ) d
where
x is the first term of sequence
d is the arithmetic difference
n is the number of term
According to question
First term = x = a..... ( 1 )
second term = x + d = b.
d = b - a. ( 2)
last term x + ( n - 1 ) * d = 2x
substituting the value of d from the above equation 2 in the equation we get
( n - 1 ) ( y - x) = x
n - 1 = x / ( y - x)
n = y / ( y - x) .. ( 3)
Hence as we know sum terms of an AP
AP = n / 2 ( 2* first term + ( n -1 ) d)
Sum = Y / 2 ( y - x) 2x +x / ( y -x) ( y -x)
Sum = 3xy / 2 ( y - x)
hence your answer is 3xy / 2 ( y - x)
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