If the fixed charges of auto rickshaw be Rs.x and the running charges by Rs.
y km/h, the pair of linear equations representing the situation is
(a) x+10y = 110 & x+15y = 75
(c) 10x+y=110 & 15x+y=75
(b) x+10y = 75 & x+15y =110
(d) 10x + y = 75 & 15.x + y = 110
Answers
Given : fixed charges of auto rickshaw be Rs. x and the running charges per km Rs. y /km
To Find : the pair of linear equations representing the situation is
(a) x+10y = 110 & x+15y = 75
(b) x+10y = 75 & x+15y =110
(c) 10x+y=110 & 15x+y=75
(d) 10x + y = 75 & 15.x + y = 110
Solution :
fixed charges of auto rickshaw = x Rs
running charges of auto rickshaw = y Rs /km
d = distance in km
Charges will be of form = x + dy where d > 0 , x , y > 0
as charges and distance can not be negative
Two Such Equations are :
x+10y = 110 & x+15y = 75
=> 5y = -35
=> y = - 7
Hence not possible
x+10y = 75 & x+15y =110
=> 5y = 35
=> y = 7
x+10y = 75
=> x + 70 = 75
=> x = 5
Hence 5 + 7d are charges
x+10y = 75 & x+15y =110 is the pair of linear equations representing the situation for d = 10 and 15
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Answer:
option b is right answer
x+10y=75 &x+15y=110