If the following triangles are similar, solve for x.
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The two ∆'s are similar,
AB/EF = AC/EG
943/1107= (45x-76)/756
943×756= 1107(45x-76)
943×84= 123(45x-76) (divided by 9)
23×84= 3(45x-76) (divided by 41)
23×28=45x-76
45x=23×28+76
45x= 644+76
x=720/45
=80/5
=16
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