Math, asked by thomasjwilkie05, 4 months ago

If the following triangles are similar, solve for x.

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Answered by dolemagar

0

The two ∆'s are similar,

AB/EF = AC/EG

943/1107= (45x-76)/756

943×756= 1107(45x-76)

943×84= 123(45x-76) (divided by 9)

23×84= 3(45x-76) (divided by 41)

23×28=45x-76

45x=23×28+76

45x= 644+76

x=720/45

=80/5

=16

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