Question

If the force on a rocket moving with velocity of 300m/s is 210N. then the rate of fuel combustion is??

Answer 1

0.7kg/s
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Answer 2

"The rate of fuel combustion is $0.7 \frac{kg}{\sec}.$

Given data:

Rocket has the force = 210 N

Velocity = 300 m/s

Solution:

Rate of combustion of the fuel can be calculated by the formula of rate of combustion,

$\left(\frac{d m}{d t}\right)=\frac{F}{u}$

The rate of combustion is the ratio of force and velocity.

Rate of combustion of fuel is dm/dt which is equal to the force per unit velocity.

$\Rightarrow \frac{dm}{dt}=\frac{210}{300}$

$\Rightarrow \frac{dm}{dt}=0.7 \frac{kg}{\sec }$"