Question

if the fourth term of an ap is 0, then a25/a11= please don't scam ​specifically fake geniuses​

Answer 1

$\dfrac{a {\tiny25}}{a{ \tiny11}} = \dfrac{ 3}{ 1}$

Step-by-step explanation:

★Given -

Fourth term of an A.P is 0.

★To find -

$\bf \dfrac{a {\tiny25}}{a{ \tiny11}}$

★Solution -

We know that,

$\bf a{ \tiny4} = 0$

$\longmapsto \bf a + 3d = 0$

$\longmapsto \bf a = - 3d \: \: \: \: \: \: \: \: \: \: \: \: \: (1)$

$\mathrm{ Now} \: , \: \bf \dfrac{a {\tiny25}}{a{ \tiny11}} = \dfrac{a + 24d}{a + 10d}$

$\longmapsto\bf \dfrac{a {\tiny25}}{a{ \tiny11}} = \dfrac{ - 3d+ 24d}{ - 3d+ 10d} {\normalsize (from \: \: 1)}$

$\longmapsto\bf \dfrac{a {\tiny25}}{a{ \tiny11}} = \dfrac{ \cancel{21d}}{ \cancel{7d}}$

$\longmapsto\bf \orange{\boxed{\dfrac{a {\tiny25}}{a{ \tiny11}} = \dfrac{ 3}{ 1} }}$

Answer 2

Answer:

?ஓஎஈஈஎஓஃழ்வௌவோCutrj37&99$7*0(?7*