Question

If the frequency of incident radiation is greater than the threshold frequency of the metal surface, then the photoelectrons are______​

Answer 1

Answer:

From Einstein's photoelectric equation, stopping potential V  

0

​

 is  

eV  

0

​

=hv−hv  

0

​

⇒V  

0

​

=  

e

h

​

(v−v  

0

​

)

Given v>v  

0

​

, so with increase of frequency v, stopping potential increases.

Explanation:

Answer 2

The answer is increased

Explanation:

• The number of photoelectrons ejected will rise with subsequent increases in incident radiation frequency.
• We know that the quantity of electrons ejected is inversely correlated with the brightness or intensity of the light.
• Only intensity, not frequency, affects the number of photoelectrons expelled. The kinetic energy of the expelled photoelectrons will rise as the frequency rises.
• Even though the intensity of the incident radiation is lower, the photoelectric emission begins instantly if the frequency of the incident radiation exceeds the threshold frequency.
• The blue of stopping potential is zero when the frequency of incident radiation reaches the threshold frequency.
• No photoelectric emission occurs when the frequency of incoming radiation falls below the threshold frequency.

Therefore If the frequency of incident radiation is greater than the threshold frequency of the metal surface, then the photoelectrons ejected will increase.

More answers:

https://brainly.in/textbook-solutions/q-multiple-choice-question-green-light-causes-emission

https://brainly.in/textbook-solutions/q-column-i-column-ii-intensity-incident-light

#SPJ2