Question

if the fundamental frequency of open organ pipe is 300. calculate second overtone of closed pipe.​

Answer 1

The fundamental frequency of an open organ pipe is 300 Hz. The first overtone of the pipe has same frequency as first overtone of a closed organ pipe. If speed of sound is 330 m/s, then the length of the closed organ pipe is. A .

Answer: The length of the closed organ pipe is 41.25 cm.

Explanation:

Given that,

Fundamental frequency of an open organ pipe = 300 hz

First overtone of open pipe = \dfrac{v}{L}

L

v

First overtone of close pipe = \dfrac{3v}{4L}

4L

3v

Speed of sound v = 330 m/s

We know that, the fundamental frequency

f = \dfrac{v}{2l} = 300 hzf=

2l

v

=300hz

First overtone of open pipe

\dfrac{v}{L} = 600 hz

L

v

=600hz

If the first overtone of an open organ pipe = first overtone of a closed organ pipe

600 = \dfrac{3\times330}{4\times L}600=

4×L

3×330

Therefore, the length of the closed organ pipe

L = \dfrac{3\times330\ m/s}{4\times 600\ s_{-1}}L=

4×600 s

−1

3×330 m/s

L = 0.4125\ mL=0.4125 m

L = 41.25\ cmL=41.25 cm

Hence, the length of the closed organ pipe is 41.25 cm.

i hope it helpfull to you

Answer 2

$\Huge{Heya\: Dost}$

_______________❤

if the fundamental frequency of open organ pipe is 300. calculate second overtone of closed pipe is $\huge{\bold{41.3cm}}$