Question

If the general term of an A.P is 4n+3 then its common difference will be​

Answer 1

Answer:

T1=7

T2=11

Common difference is 4

Explanation:

Answer 2

Answer:

• The common difference is 4.

Given:

• The general term of an A.P. is 4n + 3

To find:

• Common difference (d).

Solution:

$\sf{t_{n}}$ = 4n + 3

$\sf{\therefore{t_{1}}}$ = 4(1) + 3

$\sf{\therefore{t_{1}}}$ = 7

Also,

$\sf{t_{2}}$ = 4(2) + 3

$\sf{\therefore{t_{2}}}$ = 11

Common difference = $\sf{t_{2}-t_{1}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 11 - 3 = 4

$\sf{\therefore}$ The common difference is 4.

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Extra information:

• $\sf{t_{n}=a+(n-1)d}$

• $\sf{S_{n}=\dfrac{n}{2}[2a+(n-1)d]}$

• $\sf{S_{n}=\dfrac{n}{2}[t_{1}+t_{n}]}$