Question

If the given fig <AOB =90°, OM//NL.Find the value of <p and <q.

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Answer 1

∠CDE+∠EOD=180

∘

(CD is straight line)

∴100+4x=180(linear pair)⇒x=20

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& 3x+90+7=180 (linear pair)

∴60+90+y=180

y=180−150=30

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Answer 2

Given,
Ang. AOB = 90
OM ll NL
Ang. AOM = 13

To find,
P and Q

Solution:
First we will prove P and Q equal:-

OM ll NL. (GIVEN)
therefore,
P = Q. ....(i) (Corresponding angles)

Now,
Ang AOM = 13
Therefore,
Ang. MOL = AOB - AOM
= 90 - 13
Ang. MOL = 77

p = 77 ( as Ang. MOL = P)
Therefore,
q = 77 ( from (i) )