If the gmt at 0°longitude is 12 noon, find the local time at station A and B
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At station A:
The difference in longitude between 0° and station A is 60° towards east.
- Since it is 12 noon at 0°, the difference of time between A and 0° will be 60*4=240 mins or 4 hours
- As A is located to the east, it will be 4 hours ahead of Greenwich time: 12+4=16 hr or 4 pm
- Therefore time at station A will be 4 pm
At station B:
The difference in longitude between 0° and station B is 30° towards west.
- The difference of time between B and 0° will be 30*4=120 mins or 2 hours
- Since B is situated to the west of prime meridian, the local time at B will be 12-2 hours= 10 am
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