if the graph of 2x+ky=10k intersect X-axis at (2,0) find k
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Answered by
1
2X+Ky=10K
putting the values of (2,0)
2(2)+K(0)=10K
K=4/10
or 2/5
Answered by
0
2×2+k×o=10k (x=2 ,y=0)
4+0=10k
4=10k
k=4/10
k=2/5
4+0=10k
4=10k
k=4/10
k=2/5
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