Two identical metallic spheres, having unequal opposite charges are placed at distances 0.9 m apart in air. after bringing them in contact with each other they are again placed at the same distance apart. now the force of repulsion b/w them is 0.025n. calculate the final charge on each of them.
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use the formula
F=9×10^-9(q^2/r^2)
given r=0.9 m
then purtting the value you will get the value of q which is your answer
F=9×10^-9(q^2/r^2)
given r=0.9 m
then purtting the value you will get the value of q which is your answer
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