if the graph of equation 2x + ky = 10k , intersect x-axis at point (5,0) .find the value of k
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Answered by
3
x=5 y=0
2(5)+k(0)=10k
10=10k
k=10/10
=1
2(5)+k(0)=10k
10=10k
k=10/10
=1
Answered by
4
hey there !
given equation : 2x +ky = 10k
so it passes through (5,0) so this satisfy the equation
=) 2×5 + k×0 = 10k
=) 10 = 10k
=) k = 1
________________________
given equation : 2x +ky = 10k
so it passes through (5,0) so this satisfy the equation
=) 2×5 + k×0 = 10k
=) 10 = 10k
=) k = 1
________________________
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