if the graph (parabola) of a quadratic polynomial intersects the x-acus and y-axis at ponts (-1,0),(4,0) and (0,4) respectively, then the zeros of a quadratic polynomial are precisely
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The answer is (-1,4). because a quadratic polynomial for a graph should be in the form of y=ax(square)+bx+c so the given points (-1,0)&(4,0) only satisfies the zeros of x
And also a parabola only intersects at two pointand it is not possible to cut the axes since it passes through
(4,0)
And also a parabola only intersects at two pointand it is not possible to cut the axes since it passes through
(4,0)
basarkhan89p7a9ol:
sorry i can't understand can u upload an image of its solutions
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