Question

If the half Life of element p is 1600 years how long does it take to disintegrate 10percent of sample

Answer 1

Answer:

t=243.25 years

Explanation:

by law of radioactivity

N=Noe^-lt.......l is LAMDA

now 10 percent disintegrated so remain sample is 90 percent

No*90/100= 9No/10

substituting

9No/10= Noe^-lt

9/10= e^-lt. now half life is ln2/l. so l=ln2/1600

10/9=e^(ln2*t/1600)

putting natural log on both sides

ln(10/9)=ln2*t/1600

t=ln(10/9)*1600/ln2

t=0.105*1600/0.693

t=243.25 years

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