Question

if the Hcf and lcm of 8 and 6 are the roots of a quadratic equation then find the quadratic equation​

Answer 1

Answer:HCF(8,6)=2

LCM(8,6)=24

Then according to question

2 and 24 are zeroes of equation ax2+be+c let a=1 then,

2+24=-b/a

26=-b/1

-26=b

2×24=c/a

48=c

Then quadratic equation=x2-26x+48

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