If the HCF and LCM of two numbers are 24 and 192 respectively and one number is 48 find the other one
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Answered by
4
Answer:
lcm×hcf=a×b
24×192÷48 = b
b=96
Answered by
1
Answer:96
Given that HCF = 24
LCM = 192
Let a = 48
Find b
BY FUNDAMENTAL THEOREM OF ARITHMETIC
a*b = HCF * LCM
48*b = 24*192
b = 24*192/48
b = 4608/48
b = 96
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