Math, asked by yd330949, 3 months ago

if the HCF and LCM of two positive integers A and B are X and Y respectively then x²y²/a²b²​

Answers

Answered by kvverma152ji
0

Value of x²y²/a²b² = xy/ab

Or

Value x²y²/a²b² = 1

Given :

1st Integer = a

2nd Integer = b

H.C.F = x

L.X.M = y

To Find :

Value of x²*y²/a²b²

Solution :

Use formula :

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